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Lemma
TMUA Paper 1

TMUA Trigonometric Equations

Multiple-angle substitution, the unit circle, and counting solutions in a fixed interval.

TMUA trigonometric equations almost always pair a trig substitution with a counting question: “how many solutions does this equation have in this interval?” The bookkeeping — translating an interval in θ\theta to an interval in 3θ3\theta or 2θ+π42\theta + \tfrac{\pi}{4} and counting cosine / sine solutions there — is the actual test.

  • Multiple-angle substitution. Set ϕ=3θ\phi = 3\theta (or whatever the argument is). Convert the interval in θ\theta to the corresponding interval in ϕ\phi. Count solutions of the simpler equation in ϕ\phi, then convert each back.
  • Range of cosine / sine. 1cosx1-1 \le \cos x \le 1. An equation cosx=k\cos x = k with k>1|k| > 1 has no solutions; k=1|k| = 1 has solutions only at the unique angle.
  • Identities. cos2+sin2=1\cos^2 + \sin^2 = 1; sin(2x)=2sinxcosx\sin(2x) = 2\sin x \cos x; cos(2x)=12sin2x=2cos2x1\cos(2x) = 1 - 2\sin^2 x = 2\cos^2 x - 1 when needed.
  • Reading the interval. “In 0θ1800^\circ \le \theta \le 180^\circ” is inclusive of both endpoints. Test endpoint values explicitly.

The move. Substitute first, count second. Once the argument is a clean single variable, the interval extends accordingly and the count comes from reading the cosine / sine graph.

Worked problems on this topic

7 pages

Free to read. Each carries the full worked solution; a video walkthrough where one has been produced.