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TMUA Paper 1

TMUA Coordinate Geometry

Lines, circles, gradients, distances, and the algebra of where two shapes meet.

Coordinate geometry on TMUA Paper 1 is mostly about translating a geometric condition (parallel, perpendicular, tangent, intersection, distance) into an algebraic one and then solving. The geometry itself is GCSE-level; the test is the translation.

  • Gradients. Two lines are parallel iff their gradients are equal; perpendicular iff their gradients multiply to 1-1. The perpendicular rule is the one most often hidden inside a question that doesn’t mention perpendicularity.
  • Distance and midpoint. PQ=(x2x1)2+(y2y1)2|PQ| = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}; midpoint of PQPQ is the coordinate-average. The midpoint of a chord of a circle lies on the radius through the centre.
  • Circle equation. (xa)2+(yb)2=r2(x - a)^2 + (y - b)^2 = r^2 with centre (a,b)(a, b) and radius rr. From the expanded form x2+y2+Dx+Ey+F=0x^2 + y^2 + Dx + Ey + F = 0, centre is (D/2,E/2)(-D/2, -E/2) and radius is D2/4+E2/4F\sqrt{D^2/4 + E^2/4 - F}.
  • Line meets circle. Substitute the line into the circle equation; the resulting quadratic in xx has discriminant zero for a tangent, positive for two intersection points, negative for none.

The move. A condition about how two shapes touch or cross is always a discriminant condition once you’ve substituted one into the other. Don’t try to compute intersections explicitly when the question only needs the sign of the discriminant.

Worked problems on this topic

6 pages

Free to read. Each carries the full worked solution; a video walkthrough where one has been produced.