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Lemma
TMUA Paper 1

TMUA Stationary Points

Differentiate, set to zero, classify with the second derivative. Then read the question.

A stationary point of a curve is a point where the gradient is zero. On TMUA Paper 1, the typical pattern is: find the stationary points of a given cubic or quartic, classify them, and answer some question about their yy-coordinates, distances, or a parameter that makes them coincide.

  • Locating stationary points. Solve y=0y' = 0. Substitute back into yy for the yy-coordinates.
  • Classifying. y>0y'' > 0 at a stationary point: local minimum. y<0y'' < 0: local maximum. y=0y'' = 0: inconclusive, inspect yy' either side.
  • Parameter conditions.yy has a stationary point at x=2x = 2” is shorthand for y(2)=0y'(2) = 0.
  • Counting stationary points. A cubic has two when its derivative has two real roots, one (inflection) when the derivative has a repeated root, none when no real roots.

The move. A cubic with a positive leading coefficient always has its local maximum on the left and its local minimum on the right. (Negative leading coefficient reverses the order.) Use that as a sanity check before reaching for the second derivative.

Worked problems on this topic

7 pages

Free to read. Each carries the full worked solution; a video walkthrough where one has been produced.