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Lemma
TMUA Paper 1

TMUA Exponentials and Logarithms

Substitute, factor, solve — quadratic-in-disguise is the most common pattern on Paper 1.

TMUA does not include exe^x or lnx\ln x — the syllabus is restricted to base-aa exponentials and logarithms for real a>0a > 0, a1a \ne 1. What does show up, in nearly every Paper 1, is an exponential equation that becomes a quadratic in disguise the moment you make the right substitution.

  • Quadratic-in-disguise. Equations of the form a2xpax+q=0a^{2x} - p \cdot a^x + q = 0 become a standard quadratic under u=axu = a^x.
  • Equation between logs. logaM=logaNM=N\log_a M = \log_a N \Rightarrow M = N, provided both M,N>0M, N > 0. The positivity condition is part of the answer.
  • Change of base. log23=1/log32\log_2 3 = 1 / \log_3 2. Short identity chain, costly when forgotten.
  • Index laws under pressure. ax+y=axaya^{x+y} = a^x \cdot a^y and axy=(ax)ya^{xy} = (a^x)^y.

The move. Whenever you see akxa^{kx} and axa^{x} in the same equation, substitute u=axu = a^{x}. The first term becomes uku^k and the equation is polynomial. Solve in uu, then convert back through u=axu = a^x, checking u>0u > 0.

Worked problems on this topic

5 pages

Free to read. Each carries the full worked solution; a video walkthrough where one has been produced.